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x^2+9x+11=3x+2
We move all terms to the left:
x^2+9x+11-(3x+2)=0
We get rid of parentheses
x^2+9x-3x-2+11=0
We add all the numbers together, and all the variables
x^2+6x+9=0
a = 1; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-6}{2}=-3$
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